cfg

Task

Consider a function $F$, which takes in a string and outputs a string, having the following properties:

• For every string $x$, $|x| < |F(x)|$.
• For every strings $x$ and $y$, $F(xy) = F(x)F(y)$, where $xy$ is $x$ concatenated with $y$.

We will also construct a set of strings, $L$, in the following manner:

• $B$ is in $L$.
• If $x$ is in $L$ then $F(x)$ is also in $L$.
• If $x$ and $y$ are both in $L$ then $xy$ is also in $L$.

You are given a string $B$ and a list, $A$, of $N$ strings. Knowing that $B$ is in $L$, determine for each string from $A$ if it belongs to $L$ or not.

You will have to write a function with the following head:

std::string check (std::string (*F)(std::string), std::string B, std::vector<std::string> A)

The function should return a string, where the $i-th$ character in '1' if the $i-th$ string from $A$ belongs to $L$ and '0' otherwise.

Note that you only have the implement the check function, but you can also implement additional helping functions and / or structures or classes.

Please refer to the sample implementation (sample.cpp).

Input

The check function gets the following three arguments (in this particular order):

• The $F$ function.
• The string $B$.
• The array of strings $A$.

All the strings will only contain lowercase English alphabet letters.

For tests worth $10$ points: the length of the longest string from $A \le 10$.

For tests worth $30$ more points: the length of the longest string from $A \le 1000$.

For tests worth $10$ more points: $B$ only contains 'a's and $F$ only returns strings containing 'a's.

For tests worth $50$ more points: $|B| \le 10^5$, the length of the longest string from $A \le 10^5$.

For every testcase, $A$ contains at most $20$ strings.

Output

The check function returns a string of length equal to the length of $A$, where the $i-th$ character is $'1'$ or $'0'$ depending on whether or not the string $A[i]$ is in $L$.

Notes

Given its special type, this problem doesn't have a formal sample test case with a sample output. Here we present and explain the sample test.

Let's consider $B$ = $ab$ and $F(B) = abba$. Then:

• $ab$ is in $L$.
• $abab$ is in $L$.
• $abba$ is in $L$.
• $ababba$ is in $L$.
• $abbc$ is not in $L$.
• $abb$ is not in $L$.
• $cd$ is not in $L$.
• ...